Question

find m if x²-2mx²+16 is divisible by x+2

Answer 1

Heya !!!


Given that,


(X +2) Is a factor of the given polynomial.



(X +2) = 0



X = -2



P(X) = X² - 2MX² + 16



=> (-2)² - 2 × M × (-2)² + 16 = 0



=> 4 - 2M × 4 + 16 = 0



=> 4 - 8M + 16 = 0



=> -8M + 20 = 0


=> -8M = -20



=> M = 20/8 = 10/4 = 5/2



OR,




X² - 2MX + 16 = 0



(-2)² - 2M × -2 + 16 = 0



4 + 4M + 16 = 0



4M = -20


m = -20/4 = -5



★ HOPE IT WILL HELP YOU ★

Answer 2

Your question needs a correction :

Correct equation : x² - 2mx + 16



Solution :-


Given that (x + 2) is the factor,

So, x + 2 = 0
x = -2

Then,


x² - 2mx + 16 = 0

(-2)² - 2(-2)m + 16 = 0

4 + 4m + 16 = 0

4m + 20 =0

4m = -20

$m = - \frac{20}{4}$

m = -5




I hope this will help you



(-: