find magnetic moment of mncl2,cuso4
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Answered by
0
Answer:
For
cupric chloride
, and
titanium(III) chloride
we gots
d
9 and 1 u ( I I + ) ,isequivalenttoa.Thespinonlymomentis 1.73⋅μ B ..youwillhavetolook up the
Bohr Magneton unit
)
.
As for
cupric sulfate
we got another
d
9
system... And as for
M
n
C
l
2
we got a
d
5
system....which are GENERALLY high-spin....
μ
spin only
=
√
35
=
5.9
⋅
μ
B
...this approximation is much less likely to be valid.
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