find magnitude and direction of a vector A=(6i-8j)
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Answered by
1
Answer:
ccccc I don't known......
Answered by
3
Answer:
1st way
Given that...
a=4i-3j
b=6i+8j
so
a+b=(4i-3j)+(6i+8j)
a+b=10i+5j
so magnitude of a+b
=√(10^2+5^2)
=√(100+25)
=√(125)
=5√5
The vector a+b=10i+5j
by the diagram..
tan @=1/2
or
@=tan^-1(1/2)
so vector will make angle tan^-1(1/2) with positive x-axis
Explanation:
2nd way in 2nd image
I hope it's helpful
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