find mass% of Benzene and CCl4 if 22 g of benzene is dissolved in 122 g of CCl4.
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Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride. Answer: Mass of solution = Mass of benzene + Mass of carbon tetrachloride = 22 g + 122 g = 144 g Mass percentage of benzne = 15.28%.
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Mass percentage of benzene
= Mass of benzene / Mass of solute × 100
= 22 g / 22 g + 122 g
= 15.28 %
Mass percentage of carbon tetrachloride
= ( 100 - Mass percentage of benzene) %
= ( 100 - 15.28) %
= 84.72 %
So the required answer is = 84.72 %
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