Find mass of co2 produce when 5.8 gm of butane (c4 h10) is burnt
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Answer:
o.4 mole co2
Explanation:
Always start with a balanced equation.
2C4H10+ 13O2→8CO2 + 10H2O
Determine the molar mass of butane.
Molar Mass of C4H10:(4×12g/mol)+(10×1gmol)=58g/mol
Determine the Mole Ratios for Butane and Carbon dioxide
2mol C4H108mol,CO2 and 8mol CO2,2mol C4H10
Divide the given mass of butane by its molar mass (multiply by its reciprocal). This will give the moles of butane. Multiply times the molar ratio that places carbon dioxide in the numerator. This will give the moles of carbon dioxide.
5.8g C4H10×1mol C4H10/58.0g C4H10×8mol CO2/2mol C4H10=0.4 mol CO2
mass of CO2=0.4x44=17.6
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