Question

Find mass of co2 produce when 5.8 gm of butane (c4 h10) is burnt

Answer 1

Answer:

o.4 mole co2

Explanation:

Always start with a balanced equation.

2C4H10+ 13O2→8CO2 + 10H2O

Determine the molar mass of butane.

Molar Mass of C4H10:(4×12g/mol)+(10×1gmol)=58g/mol

Determine the Mole Ratios for Butane and Carbon dioxide

2mol C4H108mol,CO2 and 8mol CO2,2mol C4H10

Divide the given mass of butane by its molar mass (multiply by its reciprocal). This will give the moles of butane. Multiply times the molar ratio that places carbon dioxide in the numerator. This will give the moles of carbon dioxide.

5.8g C4H10×1mol C4H10/58.0g C4H10×8mol CO2/2mol C4H10=0.4 mol CO2

mass of CO2=0.4x44=17.6