find mass of O2 present in H2SO4 which has 16 g of sulphur...?
plz answer this as soon as possible.. thank u
Answers
Answered by
1
for 1 mole of sulpher 2 mole of o2 are required ,hence for 0.5 mole[16/32] ,1 mole of o2 is required .....
as of 1 mole o2 is 32g
so for 16 g of sulpher 32 g of o2 is present
KrishnaVermaOO7:
no....your method is wrong bro...u r dividing its molar mass...nd answer is 83.3 approx..
GRAMS
OE AW GYA MERA ANSWER QUESTION M GLTI H VO 6*10^23 LEKAR SHI ANSWER AW RHA H
MOLES OF OXYGEN AYEGE 1.5*10^24/6*10^23=2.5
AB 1 CACO3 K LIYE CHAHIYE 3 OXYGEN
EK OXYGEN K LIYE CHAHIYE 1/3 CACO3
hame pure CaCO3 ka mass nikalna h
2.5 MOL OXYGEN K LIYE 2.5/3 CACOR
ND MASS OF CACO3 WILL BE 2.5/3*100=83.3
AW GYA NA TOH
Similar questions