Question

find mass of oxygen required, when 5.8 g of butane is burnt​

Answer 1

Answer:

1. Hence the mass of O2.
2. required is:
3. mass = number of moles × molar mass.
4. = nM = (0.65 mol) × (32.00 g mol.

Answer 2

Answer:

20.8g

Explanation: no, of moles= given mass/molar mass=5.8/58=0.1 moles

2c4h10 needs1302

1 c4h10 needs 13/2 o2

therefore 0.1 c4h10 will require 13/2*0.1 o2=0.65 moles

no of moles=given mass/ molar mass=x/32=0.65

=20.8g