Question

Find mass of sodium that has same number of atoms as in 4 g of co2

Answer 1

Answer :-

Well we are provided with

Mass of $CO_2$ = 4g

Now as molar mass of $CO_2$ = 44 grams

Hence No. of Moles

= $\dfrac{4}{44}$

=$\dfrac{1}{11}$

Now total number of Atoms

= No of moles × No of atoms per molecule × $N_A$

= $\dfrac{1}{11} \times 3 \times 6.022 \times 10^{23}$

= $\dfrac{1.8066 \times 10^{24}}{11}$

Now as Sodium's molecular mass = 23u

Then

No of moles × No of atoms per molecule × $N_A$ = $\dfrac{1.8066 \times 10^{24}}{11}$

let no. of Moles be x

Then

$x \times 1 \times 6.022 \times 10^{23} =\dfrac{1.8066 \times 10^{24}}{11}$

$x = \dfrac{1.8066 \times 10^{24}}{11\times 6.022 \times 10^{23} }$

$x = \dfrac{3}{11} \: moles$

Now mass

= $\dfrac{3}{11} \times 23$

$= \dfrac{69}{11}$

= 6.27 grams of Na(Sodium)