find mass, volume and no. of molecules of carbon dioxide when 108g of carbon burnt in the presence of O2
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Explanation:
C + O2 --> CO2
1 mole carbon gives 1 mole CO2
no of moles in 108 gm C = given mass of C / molar mass of C
no of moles = 108 / 12 = 9 moles
Thus, 9 moles of Carbon will give 9 moles of CO2.
mass of CO2 = 9 * 44 = 396 gm
no of moleccules of CO2 = moles of CO2 * 6.022 * 10^23
= 9 * 6.022 * 10^23 = 54.2 * 10^23
= 5.4 * 10^24
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