find matrix x and y of order2×2such that 2x-3y=[2 5 3 1], 3x+2y=[7 1 4 5]
Answers
Answered by
7
2x-3y=[2 5 3 1]------eq 1
3x+2y=[7 1 4 5]-----eq 2
multiplying by 3 in eq 1 nd by 2 in eq 2 nd subtracting
we get
-9y-4y=[6 15 9 3]-[14 2 8 10]
-13y=[-8 13 1 -7]
y=[8/13 -1 -1/13 7/13]
putting the value of y in eq 1
we get
2x-3 [8/13 -1 -1/13 7/13]=[2 5 3 1]
2x-[24/13 -3 -3/13 21/13]=[2 5 3 1]
2x=[50/13 2 36/13 34/13]
x=[25/13 1 18/13 17/13]
it is the required value of x nd y
3x+2y=[7 1 4 5]-----eq 2
multiplying by 3 in eq 1 nd by 2 in eq 2 nd subtracting
we get
-9y-4y=[6 15 9 3]-[14 2 8 10]
-13y=[-8 13 1 -7]
y=[8/13 -1 -1/13 7/13]
putting the value of y in eq 1
we get
2x-3 [8/13 -1 -1/13 7/13]=[2 5 3 1]
2x-[24/13 -3 -3/13 21/13]=[2 5 3 1]
2x=[50/13 2 36/13 34/13]
x=[25/13 1 18/13 17/13]
it is the required value of x nd y
Similar questions