Physics, asked by gssidhu5133, 1 year ago

Find max ke of electron emitted by light of frequency 8× 10^14 for this metaal

Answers

Answered by sonabrainly
0

K.E ( kinetic energy ) = h ( f - f₀ ) 

           h ----- > plank's constant

           f₀ ------> Threshold frequency

           f --------> Frequency 

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         h = 6.626 × 10⁻³⁴

         f₀ = 7× 10¹⁴ Hz

         f = 1 × 10¹⁵ Hz

K.E = (6.626 ×10⁻³⁴ ) ₓ [ (1 × 10¹⁵)  - (7× 10¹⁴)]

      = 1.987 × 10⁻¹⁹ J //

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