Find max ke of electron emitted by light of frequency 8× 10^14 for this metaal
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K.E ( kinetic energy ) = h ( f - f₀ )
h ----- > plank's constant
f₀ ------> Threshold frequency
f --------> Frequency
------------------------------------------------
-------------------------------------------------------------------------
h = 6.626 × 10⁻³⁴
f₀ = 7× 10¹⁴ Hz
f = 1 × 10¹⁵ Hz
K.E = (6.626 ×10⁻³⁴ ) ₓ [ (1 × 10¹⁵) - (7× 10¹⁴)]
= 1.987 × 10⁻¹⁹ J //
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