Question

find max value of z^5 x^3 y^8 if 4x+7y+9z=10 where x,y,z>0​

Answer 1

Answer:

hey mate your answer

Step-by-step explanation:

x+2y+4z = a  _____ (1)

3x-y+5z = b  _____ (2)

2x-3y+z = c  _____ (3)

multiplying eq (1) by (3) and then subtract from (2)

3x+6y+12z = 3a

3x - y + 5z = b 

(-)  (+)  (-) = (-)

_____________

7y + 7z = 3a - b     __ __ _ __ _(4)

multiplying eq (3) by (3) & (2) by (2) then subtract

6x - 2y + 10z = 2b

6x - 9y + 3z = 3c

(-)   (+)   (-)   (-)

_____________

7y + 7z = 2b - 3c ___________ (5)

now, if given equation have more then two solution 

then

77=77=2b−3c3a−b

3a-b = 2b - 3c

3a + 3c = 3b 

a + c = b

[b - a = c]

hope it helps you