find maxima and minima of f(x)=2x³-9x²+12x+3 plzz guys
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Answered by
5
Answer:
x=2 is point of Minima and x=1 is point of Maxima.
Step-by-step explanation:
f'(x) = 6x^2 - 18x +12
f'(x) = 0
6x^2 - 18x + 12 = 0
x^2 - 3x + 2 = 0
x^2 - 2x - x +2 = 0
(x-2)(x-1) =0
f''(x) = 12x-18
For x=2, f''(x)>0
So x=2 is point of Minima of f(x).
For x=1, f''(x)<0
So, x=1 is point of Maxima of f(x).
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i did't explained steps here as i did that in the previous question,
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