Find maxima and minima of function f(x)= x³ - 18x² + 33x
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f(x) = x³ - 18x² + 33x
f'(x) = 3x² - 36x + 33
f'(x) = 0
=> 3x² - 36x + 33 = 0
=> x^2 - 12x + 11 = 0
(x - 11)(x - 1) = 0
x = 1, 11.
f''(x) = 6x - 36
Now, if x = 1, f''(x) = -30 <0
if x = 11, f''(x) = 30 >0
We know, that if f''(x) <0, f(x) is the maxima, while if f''(x) >0, f(x) is the minima.
So, at x = 1, it is maxima, while at x = 11, it is minima.
So maximum value = 1 - 18 + 33 = 16
minimum value = 1331 - 2178 + 363 = -494
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