Find maximum and minimum range of 2sin²x+4cos²x+6sinxcosx+8<br />give the relevent answer please!!!
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y=2sin²x+4cos²x+6 sinxcosx+8
as we know ,that max. and min. value of sinx and cos x is 0&1
and if sinx is 0then cosx is 1 while if cosx is 0 then sinx is 1
so max. value of y is when sinx =0,cosx=1
means 2sin²x =6sinx cosx =0
max.value =4 cos²x+8=4 ×1 +8=12
min. vqlue when cosx =0 sinx=1
means 2 sin²x+8=2×1+8=10
as we know ,that max. and min. value of sinx and cos x is 0&1
and if sinx is 0then cosx is 1 while if cosx is 0 then sinx is 1
so max. value of y is when sinx =0,cosx=1
means 2sin²x =6sinx cosx =0
max.value =4 cos²x+8=4 ×1 +8=12
min. vqlue when cosx =0 sinx=1
means 2 sin²x+8=2×1+8=10
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