Question

find maximum and minimum values of : 15 cos theta - 8 sin theta

Answer 1

hope this helps u ☺️☺️

Answer 2

Answer: The maximum and minimum values would be 17 and -17 respectively.

Step-by-step explanation:

Since we have given that

$15\cos\theta-8\sin \theta$

We need to find the maximum value and minimum value of the above expression:

Here the above expression is in the form of :

$a\cos \theta+b\sin \theta$

So, Maximum value would be $\sqrt{a^2+b^2}$

Minimum value would be $-\sqrt{a^2+b^2}$

so, the maximum value is $\sqrt{15^2+8^2}=\sqrt{225+64}=\sqrt{289}=17$

Similarly, minimum value is

$-\sqrt{15^2+8^2}=-\sqrt{225+64}=-\sqrt{289}=-17$

Hence, the maximum and minimum values would be 17 and -17 respectively.