Question

Find maximum moles of CCl4 formed when

10 moles of CH4 undergoes chlorination

with excess of chlorine:

1CH4 + 4Cl2  1CCl4 + 4HCl

(A) 2 moles (B) 5 moles

(C) 8 moles (D) 10 moles​

Answer 1

Answer:

D is correct answer

Explanation:

as per reaction 1 mole CH4 produce 1 mole of CCl4

so 10 mole of CH4 will produce 10 mole of CCl4

Answer 2

Concept:

The industrially significant process of chlorinating methane produces a mixture of chloromethane (CH₃CI), dichloromethane (CH₂CI₂), trichloromethane (CHCI₃), and tetrachloromethane (CCI₄).

Given:

The number of moles of CCl₄ = 10 moles

Find:

Find the maximum moles of CCl₄ formed when 10 moles of CH₄ undergo chlorination with an excess of chlorine.

Solution:

The complete balanced chemical reaction of CH₄ to CCl₄ is as follows below.

                             1CH₄ + 4Cl₂ → 1CCl₄ + 4HCl

Chlorine is in excess so the limiting reactant is methane (CH₄).

From the above chemical equation, we came to know that 1 mole of methane formed 1 mole of carbon tetrachloride.

So, 10 moles of methane formed 10 moles of carbon tetrachloride.

Hence, the maximum number of moles of CCl₄ formed when 10 moles of CH₄ undergo chlorination with an excess of chlorine is 10 moles.

The correct option is (D) 10 moles.

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