Find maximum value of ‘y’ where y = 2 sin theta + √5 cos theta
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Answer: 3
Y= 2Sin theta +√5 cos theta
dy/d theta = 2cos theta - √5sin theta
2cos theta = √5 sin theta
Tan theta = 2/√5
=> Sin theta = 2/3
=> Cos theta =√5/3
=> Y = 2× 2/3 +√5 ×√5/3.
Y = 4/3 + 5/3
=> Y= 9/3.
Y=3.
Answer = 3.
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