Question

find me question and give me solution

Answer 1

Find ∠ABC

∠ABC + ∠EBC = 180º (Adjacent angles on a straight line)

∠ABC + 110º = 180º

∠ABC = 180º - 110º 

∠ABC = 70º

Find ∠ACB:

∠ACB = ∠ABC (isosceles triangle)

∠ACB = 70º

Find ∠BCF :

∠BCF + ∠ACB = 180º (Adjacent angles on a straight line)

∠BCF + 70º = 180º

∠BCF = 180º - 70º

∠BCF = 110º

Answer: ∠ABC = 70º, ∠ACB = 70º, ∠BCF = 110º

Answer 2

$<b>HELLO !$
Hi, here ur answer.


we know that

X+110=180(since it is a linear pair)

X=180-110

X=70

But. y=70(since y=x) because angle opposite to same sides are equal
Now
Y+BCF=180(linear pair)

70+BCF=180

BCF=180-70

BCF=110

NOw angle z will be

since sum of all the angles of a triangle is 180

x+y+z=180

70+70+z=180

140+z=180
z=180-140
Z=40

So, I HOPE IT'S HELP YOU