Question

find mean and median denomination 10 20 5 50 100 no of notes 40 30 10 25 20​

Answer 1

N=∑f

i

=50

Here, N=50 , so

2

50

=25 and the cummulative frquency is just greater than

2

N

is 35.

Thus, 20−30 is median class.

l=lower limit of median class=20

F=Cummulative frequency before median class=15

Difference between the class=h=10

frequency of median class=f=20

Median=l+

f

2

N

−F

×h=20+

20

25−15

×10=25

∑f

i

×∣x

i

−Median∣=450

mean deviation about the mean=

N

1

∑f

I

×∣x

i

−Median∣=

50

1

×450=9