Find mean and mode for the following data of test match scores.
Scores
65
70
75
80
85
90
95
100
Frequency
2.
3
2.
5
8
7
5
3
Answers
Answered by
1
Answer:
Converting the given data into a frequency distribution table
Maths marks No. of students
(f) c.f.
60−65 8 8
65−70 12 20
70−75 14 34
75−80 8 42
80−85 5 47
85−90 6 53
90−95 4 57
N=Σf=57
Here, N=57
⟹
2
N
=
2
57
=28.5
⟹In the above table 70−75 is the median class and the respective c.f. is 20 (cumulative frequency of the class preceding the median class)
Acc to ques,
l=70 (lower limit of median class)
c.f. =20
h=l
2
−l
1
=5 (width of class interval of median class)
f=14 (frequency of median class)
Median=l+
f
2
N
−c.f.
×h=70+
14
28.5−20
×5
⟹ Median =73.05
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Answered by
0
Answer:
hope this helps
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