find mean CI=160-162,163-165,166-168,169-171,172-174
F=15,118,142,127,18
Answers
The following is the distribution of the height of students of a certain class in a certain city:
Height (in cms): 160-162 163-165 166-168 169-171 172-174
No. of students: 15 118 142 127 18
Find the average height of the maximum number of students.
Solution
Heights No. of students
159.5−162.5 15
162.5−165.5 118
165.5−168.5 142
168.5−171.5 127
171.5−174.5 18
Here, the maximum frequency is 142, then the corresponding class 165.5−168.5 is the modal class.
We know,
Mode=l+
2f−f
1
−f
2
f−f
1
×h
l= lower limit of the modal class
h= size of the class intervals
f= frequency of the modal class
f
1
= frequency of the class preceding the modal class
f
2
= frequency of the class succeed in the modal class.
⇒ l=165.5,h=168.5−165.5=3,f=142,f
1
=118,f
2
=127
⇒ Mode=165.5+
2×142−118−127
142−118
×3
⇒ Mode=165.5+
39
72
⇒ Mode=165.5+1.85=167.35cm
Answer:
Step-by-step explanation:
