find mean class interval 5-10,10-15,15-20,20-25,25-30,30-35 , frequensy 2,3,6,7,2,5
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Mean=22.5-6/25×5
=22.5-6/5
=22.5-1.2
=21.3
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Answer:
21.3
Step-by-step explanation:
We need to get the midpoint of each of the class intervals.
The midpoint (x) = (Lower limit + upper limit)/2
1: (4.5 + 10.5)/2 = 7.5 ; fx =7.5 × 2 = 15
2: (9.5 + 15.5) / 2 = 12.5 ; fx = 12.5 × 3 = 37.5
3: (15.5 + 20.5)/2 = 17.5 ; fx = 17.5 × 6 = 105
4: (19.5 + 25.5)/2 = 22.5 ; fx = 22.5 × 7 = 157.5
5: (24.5 + 30.5)/2 = 27.5 ; fx = 27.5 ×2 = 55
6: (29.5 + 35.5)/2 = 32.5 ; fx = 32.5 × 5 = 162.5
∑f = 2 + 3 + 6 + 7 + 2 + 5 = 25
∑fx = 15 + 37.5 + 105 + 157.5 + 55 + 162.5 = 532.5
Mean = ∑fx/ ∑f
= 532.5/25 = 21.3
To answer this question well we need the x (mid point column) , The fx ( frequency × midpoint) column and the frequency (f) column.
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