Question

Find mean deviation from median for data
25, 28, 32, 32, 36, 45, 45, 48, 50, 51, 53​

Answer 1

Step-by-step explanation:

40.45 sum up all the digits and divide by the no of digits

Answer 2

Answer:

The Mean deviation from median is 8.54

Step-by-step explanation:

The given data in order is,

25,28,32,32,36,45,45,48,50,51,53

The number of observations are $n=11$

Since,The number of observations are odd the median is $(\frac{n+1}{2} )th$ observation which is

$(\frac{11+1}{2} )=6th \:observation=45$

Hence the median is $M=45$

Now the mean deviation from median for following data is given by the relation

$d=\frac{\Sigma|x_{i}-M|}{n}$

Substituting the given values in the above relation,we get

$d=\frac{|25-45|+|28-45|+|32-45|+|32-45|+|36-45|+|45-45|+|45-45|+|48-45|+|50-45|+|51-45|+|53-45|}{11}$Simplifyiing the above calculation,we get

$d=\frac{20+17+13+13+9+0+0+3+5+6+8}{11} =\frac{94}{11} =8.54$

Therefore,The Mean deviation from median is 8.54

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