Question

Find Mean mode median of the following data 135,150,139,128,151,132,146,149,143,141,150​

Answer 1

$\huge\color{indigo}{\mid{\fbox{\tt{Solution :-}}\mid}}$

Given : -

⇒135, 150, 139, 128, 151, 132, 146, 149, 143, 141, 150

$\bf\:Mean=\mathtt\red{\frac{Sum \: of \: observation}{Total \:no. \: Of\: observation} }$

$\bf \: ⠀⠀⠀⠀=\frac{135 + 150 + 139 + 128 + 151 + 132 + 146 + 149 + 143 + 141 + 150 }{11}$

$\bf \: ⠀⠀⠀⠀ =\frac{1,564}{11}$

$\bf \: Mode \: ( arrange \: the \: data \: in \: \\ \bf \: ascending \: order)$

$\bf \: 135, 150, 139, 128, 151, 132, 146, 149, 143, 141, 150</p><p>\\\bf⇒128, 132, 135, 139, 141, 143, 146, 149,\underline\mathtt \red{150, 150,}151$

$\bf \: Mode \: is \: maximum \: occurring \: observation.$

$\bf\therefore\:Mode = 150$

$\bf \: Median \: (Arrange \: the \: data \: in \\ \bf \: ascending \: order)$

$\bf \: 135, 150, 139, 128, 151, 132, 146, 149, 143, 141, 150</p><p>\\\bf⇒128, 132, 135, 139, 141, 143, 146, 149,\underline\mathtt \red{150, 150,}151$

$\bf \: Median = middle \: most \: observation \: = 132$

$\bf \: No \: of \: observation= n = 11 (odd)$

$\bf \: Since ,\: n \: is \: odd$

$\bf \: Median \: = \:( \frac{n \: + \: 1}{2})$

$\bf \:⠀⠀⠀⠀⠀ =(\frac{11 \: + \: 1}{2})^{th} \: observation$

$\bf \: ⠀⠀⠀⠀⠀ =(\frac{12}{2})^{th}observation$

$\bf \: ⠀⠀⠀⠀⠀ =6^{th} \: observation$

$\bf \therefore \: median \: = 132$

Hᴏᴘᴇ Iᴛ Hᴇʟᴘs Yᴏᴜ ✌️

Answer 2

Answer:

Given : -

⇒135, 150, 139, 128, 151, 132, 146, 149, 143, 141, 150

\bf\:Mean=\mathtt\red{\frac{Sum \: of \: observation}{Total \:no. \: Of\: observation} }Mean=

Totalno.Ofobservation

Sumofobservation

\bf \: ⠀⠀⠀⠀=\frac{135 + 150 + 139 + 128 + 151 + 132 + 146 + 149 + 143 + 141 + 150 }{11}⠀⠀⠀⠀=

11

135+150+139+128+151+132+146+149+143+141+150

\bf \: ⠀⠀⠀⠀ =\frac{1,564}{11}⠀⠀⠀⠀=

11

1,564

\begin{gathered} \\ \\ \\ \\ \end{gathered}

\begin{gathered}\bf \: Mode \: ( arrange \: the \: data \: in \: \\ \bf \: ascending \: order)\end{gathered}

Mode(arrangethedatain

ascendingorder)

\begin{gathered}\bf \: 135, 150, 139, 128, 151, 132, 146, 149, 143, 141, 150 < /p > < p > \\\bf⇒128, 132, 135, 139, 141, 143, 146, 149,\underline\mathtt \red{150, 150,}151\end{gathered}

135,150,139,128,151,132,146,149,143,141,150</p><p>

⇒128,132,135,139,141,143,146,149,

150,150,

151

\bf \: Mode \: is \: maximum \: occurring \: observation.Modeismaximumoccurringobservation.

\bf\therefore\:Mode = 150∴Mode=150

\begin{gathered} \\ \\ \\ \\ \end{gathered}