find mean, mode ,median . Variable=4,6,8,10,12. Frequency=4,8,14,11,3
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Answered by
27
(x)(f) fx
4 4. 16.
6. 8 48
8. 14 112
10. 11. 110
12. 3. 36 total of fx= 322
total full =40
so mean = fx/f
=322/40
=8.05
median is (n+1)/2
=(5+1)/2
=3rd observation I.e 8
mode is the highest frequency I.e 14 3rd observation.
4 4. 16.
6. 8 48
8. 14 112
10. 11. 110
12. 3. 36 total of fx= 322
total full =40
so mean = fx/f
=322/40
=8.05
median is (n+1)/2
=(5+1)/2
=3rd observation I.e 8
mode is the highest frequency I.e 14 3rd observation.
Answered by
8
Mean = 8.05
Median = 8
Mode = 8
- CALCULATION OF MEAN:
- Frequency Table
x f fx
4 4 16
6 8 48
8 14 112
10 11 110
12 3 36
TOTAL 40 282
Mean =
= 322/40
= 8.05
- CALCULATION OF MEDIAN:
- Given observations as per the given frequency are
4, 4, 4, 4, 6, 6, 6, 6, 6, 6, 6, 6, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 12, 12, 12
N = 40
N + 1 = 40 + 1 = 41
(N+1)/2 = 20.5
Median = (N+1)/2th observation
= 8
- CALCULATION OF MODE:
- Mode = observation with highest frequency
= 8
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