Find mean with direct method
Attachments:

Answers
Answered by
2
Here, the class intervals are formed by the exclusive method. If we make the series an inclusive one the mid-values remain same. So there is no need to convert the series.
Let the assumed mean be A = 60 and h = 3
so ui=xi−Ah=xi−603
Calculation of Mean
104-640x375 22222
Therefore x¯=A+hΣfiuiΣfi=60+3×−375400
= 60 – 2.8125 = 57.1875
= 57.19(nearly)
Hence, average number of mangoes per box = 57.19 (nearly)
HOPE IT IS HELP YOU
Let the assumed mean be A = 60 and h = 3
so ui=xi−Ah=xi−603
Calculation of Mean
104-640x375 22222
Therefore x¯=A+hΣfiuiΣfi=60+3×−375400
= 60 – 2.8125 = 57.1875
= 57.19(nearly)
Hence, average number of mangoes per box = 57.19 (nearly)
HOPE IT IS HELP YOU
Answered by
2
Sol. Here, the class intervals are formed by the exclusive method. If we make the series an inclusive one the mid-values remain same. So there is no need to convert the series.
Let the assumed mean be A = 60 and h = 3
so ui=xi−Ah=xi−603
Calculation of Mean
104-640x375 22222
Therefore x¯=A+hΣfiuiΣfi=60+3×−375400
= 60 – 2.8125 = 57.1875 = 57.19(nearly)
Hence, average number of mangoes per box = 57.19 (nearly).
HOPE IT IS HELP YOU
Let the assumed mean be A = 60 and h = 3
so ui=xi−Ah=xi−603
Calculation of Mean
104-640x375 22222
Therefore x¯=A+hΣfiuiΣfi=60+3×−375400
= 60 – 2.8125 = 57.1875 = 57.19(nearly)
Hence, average number of mangoes per box = 57.19 (nearly).
HOPE IT IS HELP YOU
jashankaler143:
vekh li
Similar questions