Math, asked by monirul5471, 1 year ago

Find measure of central angle of the sector whose perimeter is 25 cm and radius of the circle is 7 cm?

Answers

Answered by nerdyme
6
perimeter of sector js
theta*pi*r=25
now r=7
so
theta is 25/22 radian

jeetfamep4l82q: perimeter of sector = lenght of arc+2r
jeetfamep4l82q: P = rθ+2r, 25= 7θ+14, 11/7(radian) = θ , hence θ = 90º
Answered by pinquancaro
11

Answer:

The measure of central angle is 90 degrees.

Step-by-step explanation:

Given : Sector perimeter is 25 cm and radius of the circle is 7 cm.

To find : Measure of central angle of the sector?

Solution :

We know, The perimeter of sector is defined as

P=l+2r

where, l is the length arc and r is the radius.

P=25 cm , r=7 cm

25=l+2(7)

25=l+14

l=25-14

l=11

So, The length of the arc is 11 cm.

Angle subtended by a circle is 360 degrees

Circumference of circle is given by,

C=2\pi r\\C=2\times \frac{22}{7}\times 7\\\\C=44cm

Angle subtended by arc is given by,

\theta = 360\times \frac{l}{C}

\theta = 360\times \frac{11}{44}

\theta =\frac{360}{4}

\theta =90^\circ

Therefore, The measure of central angle is 90 degrees.

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