Math, asked by naresh6951, 10 months ago

Find measure of the angles A and B If cos A - B = √3/2 and sin A + B = √3/2​

Answers

Answered by Anonymous
41

Answer :-

  • B = 15°
  • A = 45°

Step By Step Explanation :-

Refer the above provided attachment

Attachments:
Answered by Anonymous
2

Given,

cos \: a - b =  \sqrt{ \frac{3}{2} }

A - B = 30°

A = 30+ B -------> 1

sin \: a  + b =  \sqrt{ \frac{3}{2} }

A + B = 60° -------->2

From equation 1 and 2

= 30+B+B=60°

30+2B=60

2B=60-30

2B=30°

b =  \frac{30}{2}

so,

B = 15°

A = 30+B

A = 30+15

A = 45°

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