find measure x and y in the following
(steps and correct answer)
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AB is the transversal
So angle CAE = angle ABC
X-60+2y+25= 180
X+2y -35 = 180
X+2y = 215.............. Eq (1)
AC is the transversal
So angle BAD = Angle ACB
3x+40+y+20 = 180
3x + y = 120......... Eq (2)
Multiply eq1 with 3 so you will get = 3x+6y= 645......
Now solve both the equations by elimination method you will get y = 105 and x= 5
Hope this will help you.. Plzz mark me in the brainlist
So angle CAE = angle ABC
X-60+2y+25= 180
X+2y -35 = 180
X+2y = 215.............. Eq (1)
AC is the transversal
So angle BAD = Angle ACB
3x+40+y+20 = 180
3x + y = 120......... Eq (2)
Multiply eq1 with 3 so you will get = 3x+6y= 645......
Now solve both the equations by elimination method you will get y = 105 and x= 5
Hope this will help you.. Plzz mark me in the brainlist
9960607673:
thanks for solving but ur ans is wrong according to my tb
What is the ans given in ur tb
x=50,y=45
Wait let me solve in another method.. And i will say u the ans u verify it
ok..
Sry iam not getting. U plzz recheck ur ans or refer any example given on ur tb...
Actually idont have any idea abt which tb ur following.. And which class ur studying.. But according to me ican solve only with this process
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