Question

find measurr of angles A and B . If cos A-B = √3/2 , sinA+B= √3/2​

Answer 1

Answer:

cosA-B=√3/2

cosA-B=cos30

therefore

A-B=30

A=30+B. ......1

now,

sinA+B=√3/2

sinA+B=sin60

therefore,

A+B=60. .......2

putting the value of 1on 2,

30+B+B=60

2B=60-30

B=30/2

B=15°

and

A=30+B

= 30+15

=45°

thus,

A=45°

B=15°

hope you like it.,

Answer 2

Step-by-step explanation:

cos(a-b) = √3/2

we know that, cos30 = √3/2

cos(a-b) = cos30

a-b = 30 (eq.1)

now , sin(a+b) = √3/2

we know that , sin60 = √3/2

sin(a+b) = sin60

(a+b) = 60 (eq.2)

adding eq.1 and 2

a-b+a+b = 30 + 60

2a = 90

a = 45

put value of a in eq.1

a-b = 30

45 - b = 30

b = 45 - 30

b = 15