Find Median
Frequency
3
8
9
10
3
0
0
2
Class - Internal
15-20
20 - 25
25 - 30
30 - 35
35 - 40
40-45
45-50
50-55
Answers
Answered by
0
Answer:
Class Frequency (f
i
) c.f.
5−10 5 5
10−15 6 5+6=11
15−20 15 11+15=26
20−25 10 26+10=36
25−30 5 36+5=41
30−35 4 41+4=45
35−40 2 45+2=47
40−45 2 47+2=49
∑f
i
=49
Where c.f.= cumulative frequency
Median =L+
⎩
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎧
h×
f
(
2
N
−c.f.)
⎭
⎪
⎪
⎪
⎬
⎪
⎪
⎪
⎫
Here
N=49
2
N
=24.5
c.f. just greater than 24.5 is 26
Median class =15−20
So, L=15, h=5, f=15 and
c.f.=c.f. of preceding class i.e 11
Substitute all the value in the above formula, we get
Median =15+(
15
24.5−11
)×5
Median =15+4.5=19.5
Thus, median of frequency distribution is 19.5.
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