Question

find median of 60,33,61,44,48,51​

Answer 1

Answer:

Step-by-step explanation:ARRANGE IN ASCENDING ORDER

33,44,48,51,60,61

NO. OF OBSERVATIONS(n) =7(ODD)

MEDIAN=n+1/2

=7+1/2

=8/2

=4

THEREFORE, MEDIAN IS 51

HOPE IT HELPS YOU

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Answer 2

Answer:

$\Large\boxed{49.5}$

Step-by-step explanation:

GIVEN:

Find the median of 60, 33, 61, 44, 48, and 51.

SOLUTIONS:

First, you have to find the median of 60, 33, 61, 44, 48, and 51 from left to right numbers.

Numbers in ordered:

33, 44, 48, 51, 60, and 61.

Numbers did not ordered:

60, 33, 61, 44, 48, and 51.

Solve.

The number of terms of the data set is 6.

If the number of terms are even, median should also have average two middle elements.

Middle elements are:

48, and 51.

Solve.

Divide the numbers from left to right.

$\displaystyle99\div2=\boxed{49.5}$

$\Large\boxed{49.5}$

Therefore, the median of 60, 33, 61, 44, 48, and 51 is 49.5.