Question

find median of first 10 composite numbers

Answer 1

first 10 composite numbers:
☛4,6,8,9,10,12,14,15,16,18 

number of terms
☛10 [ even number is given ]
median = average of [10,12]
 = [10+12]/2
=22/2
=11

Answer 2

Answer:

11

Step-by-step explanation:

Composite number : A composite number is a positive integer that can be formed by multiplying two smaller positive integers.

First 10 composite numbers = 4, 6, 8, 9, 10, 12, 14, 15, 16, 18

Number of terms = 10 even

So, Median = $\frac{\frac{n}{2}\text{th term} +( \frac{n}{2}+1)\text{th term}}{2}$

                    = $\frac{\frac{10}{2}\text{th term} +( \frac{10}{2}+1)\text{th term}}{2}$

                    = $\frac{5\text{th term} +6\text{th term}}{2}$

                    = $\frac{10+12}{2}$

                    = $11$

Hence  median of first 10 composite numbers is 11