Question

Find mid point of the line joining (3,-5) &
(-3,-3)
Options
O (0,-4)
O (-4,0)
O (0,4)
O (4,0)​

Answer 1

Answer:

The coordinates of the midpoint of line joining the given points are ( 0, - 4).

First option ( 0, - 4 )

Step-by-step-explanation:

The given coordinates of the points are

• ( 3, - 5 ) ≡ ( x₁, y₁ )
• ( - 3, - 3 ) ≡ ( x₂, y₂ )
• Midpoint ≡ ( x, y )

We have to find the coordinates of the midpoint of line joining these two points.

Now, by midpoint formula,

$\displaystyle{\boxed{\pink{\sf\:x\:=\:\dfrac{x_1\:+\:x_2}{2}}}\sf\:\quad\:,\:\quad\:\boxed{\pink{\sf\:y\:=\:\dfrac{y_1\:+\:y_2}{2}}}}$

$\displaystyle{\implies\sf\:x\:=\:\dfrac{3\:+\:(\:-\:3\:)}{2}\:\quad\:,\:\quad\:y\:=\:\dfrac{-\:5\:+\:(\:-\:3\:)}{2}}$

$\displaystyle{\implies\sf\:x\:=\:\dfrac{3\:-\:3}{2}\:\quad\:,\:\quad\:y\:=\:\dfrac{-\:5\:-\:3}{2}}$

$\displaystyle{\implies\sf\:x\:=\:\dfrac{0}{2}\:\quad\:,\:\quad\:y\:=\:\dfrac{-\:\cancel{8}}{\cancel{2}}}$

$\displaystyle{\implies\sf\:x\:=\:0\:\quad\:,\:\quad\:y\:=\:-\:4}$

$\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:(\:x\:,\:y\:)\:=\:(\:0\:,\:-\:4\:)\:}}}}$

∴ The coordinates of the midpoint of line joining the given points are ( 0, - 4).

Answer 2

★GIVEN:-

• joining (3,-5) &(-3,-3)

★FIND:-

• mid point of the line

★option:-

• A (0,-4)

• B (-4,0)

• C (0,4)

• D(4,0)

★SOLUTION:-

• we know that cordinet distance midpoint between formula

• x cordinet

$\implies \red{ x = \frac{ x_{1} + x_{2} }{2} }$

• y cordinet

$\implies \green{y = \frac{ y_{1} + y_{2} }{2} }$

• where

$\implies{ x_{1} } = 3\\ \\ \implies \: x_{2} = - 3 \\ \\ \implies \: y_{1} = - 5 \\ \\ \implies \: y_{2} = - 3$

• now we put value in formula

x cordinet

$\implies \: x = \frac{3 - 3}{2} \\ \\ \implies \: x = \frac{0}{2} \\ \\ \implies \: x = 0$

y cordinet

$\implies \: y = \frac{ - 5 - 3}{2} \\ \\ \implies \: y = \cancel{\frac{ - 8}{2} } \\ \\ \implies \: y = - 4$

midpoint=(0,-4)

answer

option A is correct

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i hope it helps you