find middle term of sequence formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th
Answers
A.P: 103, 110, 117, ...., 999
a = 103 d = 7
n be the number of terms
= 999
103 + (n - 1)7 = 999
103 + 7n - 7 = 999
7n + 96 = 999
7n = 903
n = 129
Middle term = term = = a + 64d = 103 + 64 x 7 = 551
= [2a + (n - 1)d]
= [2 x 103 + 63 x 7] = 20704
= [2 x 103 + 128 x 7] = 71079
- ( + 551) = 71079 - (20704 + 551) = 49824
Hope it helpful
Given: SP║RQ, ∠R = 90° and ∠Q = 130°.
To find: The measure of ∠P.
Answer:
It is given that SP║RQ. So let us assume that PQ is the transversal.
Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)
∠P + 130° = 180°
∠P = 180° - 130°
∠P = 50°
Now let us assume that SR iigit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th
s the transversal.
d middle term of sequence sequed by 4 also find the sum of all number on the both side of the middle term CBSE class 10th
ence formed by all three digit numbers which leave erm of sequence formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th
a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th
formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the bot
Therefore, ∠S + ∠R = 180° (Co - interior Angles are Supplementary)
∠S + 90° = 180°
∠S = 180° - 90°
∠S = 90°