Question

find middle term of sequence formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th

Answer 1

Hello mate!!


A.P: 103, 110, 117, ...., 999

a = 103  d = 7

n be the number of terms

= 999

103 + (n - 1)7 = 999

103 + 7n - 7 = 999

7n + 96 = 999

7n = 903

n = 129

Middle term =  term = = a + 64d = 103 + 64 x 7 = 551

=  [2a + (n - 1)d]

=  [2 x 103 + 63 x 7] = 20704

=  [2 x 103 + 128 x 7] = 71079

- ( + 551) = 71079 - (20704 + 551) = 49824


Hope it helpful

Answer 2

Given: SP║RQ, ∠R = 90° and ∠Q = 130°.

To find: The measure of ∠P.

Answer:

It is given that SP║RQ. So let us assume that PQ is the transversal.

Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)

∠P + 130° = 180°

∠P = 180° - 130°

∠P = 50°

Now let us assume that SR iigit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th

s the transversal.

d middle term of sequence sequed by 4 also find the sum of all number on the both side of the middle term CBSE class 10th

ence formed by all three digit numbers which leave erm of sequence formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th

a remainder 3 when divided by 4 also find the sum of all number on the both side of the middle term CBSE class 10th

formed by all three digit numbers which leave a remainder 3 when divided by 4 also find the sum of all number on the bot

Therefore, ∠S + ∠R = 180° (Co - interior Angles are Supplementary)

∠S + 90° = 180°

∠S = 180° - 90°

∠S = 90°