Find minimum number of electrons for what n+m+l=5 and l is not equal to 0
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⭐⭐⭐hey mate!⭐⭐⭐
For,
n+m+l=5
Putting n=4
m=-2 ,-1 ,0,+1,+2
l=1
Configuration
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Up to 4p
Becoz here n=4
p=1
Taken m=0
And m+l+n=5.....
In above configuration... Possibility of orbits
3p.........(2) electrons
3d..........(2) electrons
4p..........(2) electron
Hence.. minimum number of electrons are 6
As for m=0 or any orbital minimum 2 electrons are 2
Hope it will help you...
#phoenix
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