Question

Find minimum numbers which can be divisible by integers lies between 3 and 8.​

Answer 1

Answer:

3, 5 and 7 are prime. 4 = 2*2; 6= 2*3; 8=2*2*2. So to be divisible by all of these, a number has to have all of these factors: 3*5*7*2*2*2 = 840. The smallest positive number divisible by all of the numbers from 3 to 8 is 840.

But "smallest" can be negative. Any negative multiple of 840 qualifies. And there is no "smallest" such number, as if 840*(-n) qualifies, so does 840* (-[n+k]) for all positive integers k.