Math, asked by h0k, 17 days ago

find minimum point of √(x^2+y^2)

Answers

Answered by ranibansiwal85

0

Answer:

x²+y²+6x+12=

x²+6x+9+y²+3=(x+3)²+y²+3

Thus minimum value =3 for x=-3 and y=0.

Step-by-step explanation:

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