Question

Find minimum value for
f(0) = 2x² - 400​

Answer 1

ANSWER:—

f(0) = 2x^2 -400

f(0)=-400.

Hence, there will be no real value of x.

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Answer 2

Answer:

Step-by-step explanation:

f(x)=2x^2-400

Differentiate w.r.t. x

f'(x)=4x

For maxima and minima

Put f'(x)=0

So,4x=0

Thren,x=0

Then again diff w.r.t x

We get,f''(x)=4 which is greater than zero i.e. point of minima

And minimum value is

f(0) =2(0)^2-400

f(0) =-400