Question

Find Minimum value of :
Sec ^2(x) + 9 losec ² (x) = ?​

Answer 1

Step-by-step explanation:

Sec²x + 9Cosec²x=?

We know that

cosec²x-sec²x=1

cosec²x=1+sec²x

PUTTING THE VALUE OF COSEC²X

Sec²x+9Cosec²x

=Sec²x + 9(1+sec²x)

=Sec²x+9+9sec²x

= (10sec²x+9).......

I HOPE IT HELPS YOU....