Find minimum value of
x/logx
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Answer:
f (x) = x / log x
f’ (x) = [log x – 1] / [log x]2
For maxima and minima put f’ (x) = 0.
log x – 1 = 0
x = e
f’’ (e) = [(1 / e) – 0] / 1 = (1 / e) > 0
f (x) is minimum at x = e.
The minimum value of x at x = e is f (e) = e / [log e] = e.
Step-by-step explanation:
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