Question

find missing no in following series 38,26,21,?please fast with solution

Answer 1

hope it helps
mark brainliest

Answer 2

Missing no. is 23.

38, 26, 21, 23.

Let the fourth term of the sequence be 'x'.

Thus the terms are 38, 26, 21, x.

The logic lies that if the difference between the first and second term is considered to be D₁ and if the difference between the second and third term is considered to be D₂, then

D₁ - D₂ should be equal to 7.

When first term is 38 and second term is 26 and third term is 21, then

D₁ = 38 - 26 = 12

and D₂ = 26 - 21 = 5

So, D₁ - D₂ = 12 - 5 = 7

When first term is 26 and second term is 21 and third term is x, then

D₁ = 26 - 21 = 5

and D₂ = 21 - x = (21 - x)

So, D₁ - D₂ = 5 - (21 - x) = x - 16

As D₁ - D₂ = 7, so

x - 16 = 7

⇒ x = 7 + 16 = 23

x = 23