find missing no.in this figure
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5,6,4 are in circumference of 1 st triangle
6^2 - 5^2 = 36 -25 = 11
Now 4^2 -11 = 16 -11 = 5
5 is in the triangle 1 st
2) 6,7,5 in circumference
7^2 - 6^2 = 49 -36 = 13
5^2 -13 = 25 - 13 = 12
Now reverse 12
So its 21
Which is in triangle 2
So
3) 4,8,10 is in circumference
8^2 -4^2 = 64 -16 = 48
10^2 -48 = 100 -48 = 52
Reverse 52
So its 25
Hence 25 is Ans
amankashyap28:
bro it's answer is 16 kindly give suitable sollution
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