find missing number in
7,9,(30),4,5;
17,8,(50),6,3;
10,21,(?)6,3
Answers
Answer:
The missing numbers are 30, 50 and 62 respectively.
Explanation:
Consider the first series (i) 7,9,(30),4,5
a. Let us find how 30 is the middle number in steps
b. Add all then numbers in the series, 7 + 9 + 4 + 5 = 25
c. Multiply the sum obtained by 2, it becomes 25 * 2 = 50
d. Multiply the last two terms in the series, 4 * 5 = 20
e. Subtract 50 – 20 = 30, which is the third term in the series
Apply these rules for the second series and check
(ii) 17, 8, (50), 6, 3
a. Let us find how 50 is the middle number in steps
b. Add all then numbers in the series, 17 + 8 + 6 + 3 = 34
c. Multiply the sum obtained by 2, it becomes 34 * 2 = 68
d. Multiply the last two terms in the series, 6 * 3 = 18
e. Subtract 68 – 18 = 50, which is the third term in the series
(iii) 10, 21, (?), 6, 3
a. Let us find the middle number in steps
b. Add all then numbers in the series, 10 + 21 + 6 + 3 = 40
c. Multiply the sum obtained by 2, it becomes 40 * 2 = 80
d. Multiply the last two terms in the series, 6 * 3 = 18
e. Subtract 80 – 18 = 62, which is the third term in the series
Answer:
THE MISSING NO 30 , 60 , 52.
Step-by-step explanation: