Math, asked by sharmasrishti92, 1 month ago

find missing number in series? 4,18?100,180,294,448​

Answers

Answered by RainCloud
4

Series is in the form of n(n+1)²

Where n starting from 1

n>=1 and n<=7

Take a Look at this series :

1*2² = 4

2*3² = 18

3*4² = 48

4*5² = 100

5*6² = 180

6*7² = 294

7*8² = 448

So, again answers is 48.

Answered by mufiahmotors
1

Answer:

You can find this series by many ways.

Take a look

Solution I.

Series is (n³-n²)

Where n starting from 2

n>=2 and n<=8

Take a Look at this series :

2³- 2² = 8 - 4 = 4

3³ - 3² = 27 - 9 = 18

4³ - 4³ = 64 - 16 = 48

5³ - 5² = 125 - 25 = 100

6³ - 6² = 216 - 36 = 180

7³ - 7³ = 343 - 49 = 294

8³ - 8³ = 512 - 64 = 448

So, answers is 48.

Solution ii.

Series is in the form of n(n+1)²

Where n starting from 1

n>=1 and n<=7

Take a Look at this series :

1*2² = 4

2*3² = 18

3*4² = 48

4*5² = 100

5*6² = 180

6*7² = 294

7*8² = 448

So, again answers is 48

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