Question

find mode of the following​

Answer 1

Step-by-step explanation:

modal class = 20-30

lower boundary = 20

h= 10

f1=40

f0=24

f2=36

mode = 20 +(40-20/2(40)-24-36)10

= 20 +(16 /20)10

= 20 + 8

= 28

note : I have not mentioned formula so try to understand it

Answer 2

Answer:

Mode = l + ( f1 - fo / 2f1 - fo - f2)x h

= 20 + (40 - 24/2x40 - 24 - 36) x 10

= 28

here the maximum class frequency is 40 and the class corresponding to this frequency is 20-30

Now,

l = lower limit of modal class = 20

f1 =frequency of the modal class = 40

fo = frequency of the class preceeding

modal class = 24

f2 = frequency of the class succeeding

modal class = 36

h = class size = 10

HOPE IT HELPS YOU