Question

find mode of the following frequency distribution 15-20 20-25 25-30 30-35 35-40 40-45 frequency 3 8 9 10 3 2​

Answer 1

Answer:

30.625

Step-by-step explanation:

CI            F

15-20      3

20-25     8

25-30     9

30-35     10    <<<MODAL CLASS

35-40     3

40-45     2

(30-35) is modal class since it has highest frequency

therefore,

L=30

H=5

F0=9

F1=10

F2=3

Therefore,

MODE=L+(f1-f0/2f1-f0-f2)H

          =30+(10-9/20-9-3)*5

          =30+(1/8)*5

          =30+0.625

          =30.625

Answer 2

Mode of given frequency table is 30.625

Given:

Class__ frequency

15-20__3

20-25__8

25-30__9

30-35__10

35-40__3

40-45__2

To find:

• find mode of the above frequency distribution.

Solution:

Formula to be used:

$\bf Mode = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right)h$

where

l= lower limit of the class.

f0= freq. of preceding of modal class

f1=freq. of modal class

f2=freq. of successive of modal class

h= height of class

Step 1:

Find modal class.

The modal class is the class that has higher frequency.

Thus,

Modal class is 30-35

Step 2:

Write all values used in formula.

l= 30

f0=9

f1=10

f2=3

h=5

Step 3:

Put the values in the formula.

$Mode = 30+ \left( \frac{10 - 9}{20 -9 - 3 } \right)5$

or

$Mode = 30+ \frac{5}{8 }$

or

$Mode = 30+ 0.625$

or

$\bf Mode = 30.625$

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