Question

find modulus of
(a) (1-i) (√3+i)/3-4i
(b) (3+2i)^2/(1-√3i)^3
(c) z1+z2+1/z1-z2+i where z1 is 2-i,z2 is 1+i

plz do it fast .. it's urgent​

Answer 1

Answer:

Solution. (i)(2+3i3 +4i)(2-3i3-4i)=[4-9i29-16i2]...(Using (a+b)(a-b) =a2-b2) Now, using i2=-1, =[4+99+16]=1325

Step-by-step explanation:

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