Question

Find molality of 0.5 molar NaNO3 solution. If density of solution is 1.2g/ml

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Answer 1

Answer:

Here Molarity(M) and density is given,

so first we have to find molar mass of NaNO3

i.e.  NaNO3 = 23 + 14 + 3(16) = 85

now to find molality there is direct formula

i.e   m = M  * 1000/(d * 1000) - (M * molar mass)

          = 0.5 * 1000/ (1.2 * 1000) - (0.5 * 85)

          = 500 / 1200 - 42.5

          =  500 / 1157.5

          = 0.43 m

So, molality of solution is 0.43 m .

Hope it helps you.

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